576=2x^2+10x

Solution for 576=2x^2+10x equation:

576=2x^2+10x

We move all terms to the left:

576-(2x^2+10x)=0

We get rid of parentheses

-2x^2-10x+576=0

a = -2; b = -10; c = +576;
Δ = b2-4ac
Δ = -102-4·(-2)·576
Δ = 4708
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4708}=\sqrt{4*1177}=\sqrt{4}*\sqrt{1177}=2\sqrt{1177}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{1177}}{2*-2}=\frac{10-2\sqrt{1177}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{1177}}{2*-2}=\frac{10+2\sqrt{1177}}{-4}
$